4 ms·
A regular computer can already represent i. You can do complex math on them fine, it's just a matter of specifying what the bits mean and the rules they follow.
by kadoban 7y ago
A regular computer can already represent i. You can do complex math on them fine, it's just a matter of specifying what the bits mean and the rules they follow.
I don't think that has anything to do with quantum or not, and I'm not sure what there is to "solve" about the sqrt(-1). We know what it is, it's just called i in the complex numbers (by definition). There's not another level to go down and explore. (in some other number systems, like the reals, sqrt(-1) just doesn't exist because no number times itself is -1).
- throwawaymath 7y agoFor example by representing numbers as pairs (a, b), where the real part is a and the imaginary part is b. Then: 1 = (1, 0) i = (0, 1) 2 + 3i = (2, 3) and so on.