4 ms·

V*A means you can vary V or A and get a higher wattage. So, you contradict yourself :)

• bluGill 7y ago
  W can be constant, in which case there is no contradiction. Of course then V=IR means I need to change R as well. However this is all math. You can choose to hold any one factor constant and change the others to fix your needs. In the real world V is a constant outside your control (120 in the US, 220 elsewhere), and A is limited by local wiring conventions (which means realistically the amount of watts you can get is different - but this is not a factor of voltage). The only factor you can change is R, which turns out to be easy enough (in this application).
  • zokier 7y ago
    P=I²R, so decreasing voltage and increasing current means increasing resistive losses (in cabling etc) quadratically.
    • bluGill 7y ago
      That is insignificant as the cables are over sized and codes account for this to ensure they are. That isn't to say you are wrong, just that it doesn't matter.
  • Dylan16807 7y ago
    You can't improve R because it's already the maximum that the circuit can handle. A is in practice the same across regions. V is the only factor that ends up mattering.