4 ms·
Swift has it. I'm sure a few languages must have it. if (2...4).contains(x)
by zapzupnz 8y ago
Swift has it. I'm sure a few languages must have it.
if (2...4).contains(x)
- hyperpape 8y agoDoes that work for floats?
- saagarjha 8y agoYes, if you use the pattern matching operator I suggested to the original comment's author: $ swift Welcome to Apple Swift version 4.2.1 (swiftlang-1000.11.42 clang-1000.11.45.1). Type :help for assistance. 1> let x = 3 x: Int = 3 2> let y = 3.0 y: Double = 3 3> 2...4 ~= x $R0: Bool = true 4> 2...4 ~= y $R1: Bool = true
- hyperpape 8y agoFloats that aren’t equivalent to ints: 2.5. In some languages, similar constructs test membership in a list/range, rather than an inequality.
- saagarjha 8y agoThis doesn't work for me: $ swift Welcome to Apple Swift version 4.2.1 (swiftlang-1000.11.42 clang-1000.11.45.1). Type :help for assistance. 1> let x = 3 x: Int = 3 2> if x in 2...4 {} error: repl.swift:2:6: error: expected '{' after 'if' condition if x in 2...4 {} ^ Are you sure you didn't mean to use if case? if case 2...4 = x
- zapzupnz 8y agoYeah, I was wrong. I updated my comment. I think I just meant to check if a range contains a value, as I changed it to.