3 ms·

I think he means rounding to 6 decimal places. If I do that I get 9.326312.

• Dylan16807 8y ago
  I...how? That's the same on most of the numbers, but even more precision on one of them. Here's my calculator, with exactly three decimal places: 25->rad: .436 sin(.436): .422 cos(.422): .912 tan(.912): 1.292 atan(1.292): .912 acos(.912): .422 asin(.422): .435 .435->deg: 24.924 Where does your calculator start to diverge, that you end up with an answer like 9? And I got the same result as Aardwolf that the Sinclair emulator returns .434, only a tenth of a degree off. Edit: Oh wait, you're using a calculator set to degrees. That's a totally different problem, because it makes the 0-1 output from sin and cos become an extremely small fraction of a circle. It works as a type of precision test, but it's not at all the same thing you'd try on the Sinclair that only does radians. It still doesn't explain your original memory. Side note: Even in degrees mode, the answer for 6 digits is kind of an outlier. If you use 5 or fewer digits the calculation crashes. 7 digits gets you 24.9. It boils down to just acos(cos( [about half a degree] )), and the other operations don't really matter.
  • jonsen 8y ago
    ...but it's not at all the same thing you'd try on the Sinclair that only does radians. Right. Apparently I wasn’t aware of that at the time. Nice to find out here on HN some fourty years later :-)