5 ms·
Usually that means a read-heavy workload where things fit in RAM.
by stingraycharles 8y ago
Usually that means a read-heavy workload where things fit in RAM.
- blattimwind 8y agoThat's a literal quote from the article. The benchmark was done entirely done in-memory.
- imtringued 8y agoThere is no such thing as no I/O. If you're latency bound by the round trip to main memory then SMT will still have a noticeable benefit. The most important thing it can't help with is if you are compute bound.
- BeeOnRope 8y agoNobody calls "trips to memory" I/O though. Yes SMT can have a benefit but the OP was asking about the case with more threads than logical cores, so SMT is already maxed out (assuming all threads are CPU bound).
- rbanffy 8y ago> SMT will still have a noticeable benefit YMMV. SMT usually halves the cache size usable by each thread. If your memory access is heavily local, enabling SMT can hurt your performance.