4 ms·
No because children are distinguishable. If you flip two coins, you get HH, HT, TH, and TT with equal probability. Try it.
by cecilpl2 9y ago
No because children are distinguishable.
If you flip two coins, you get HH, HT, TH, and TT with equal probability. Try it.
- KozmoNau7 9y agoBut the sequence is irrelevant. HT is equal to TH, because in this situation we only care whether the two coins are equal to each other or different from each other.
- Dylan16807 9y agoIt's the percent chance that matters, so it doesn't matter if you can distinguish them. The cases still exist with equal chance.
- deleted 9y ago[deleted]
- KozmoNau7 9y agoThe first child is not an influencing factor on the second child. It's either a boy or a girl, 50/50.
- KozmoNau7 9y agoTo elaborate, the situation as stated in the question is currently Hx, so HH and HT are the only possible results.
- Dylan16807 9y agoYou can calculate 50/50 but it's not by ignoring the difference between HT and TH.