4 ms·
Because then you are compromising the utility of your url-as-search semantics, complicating your implementation, and probably distorting your data and/or schema
by s17n 9y ago
Because then you are compromising the utility of your url-as-search semantics, complicating your implementation, and probably distorting your data and/or schema. A better solution is to make the distinction between "display" and "permanent" url a first class concept.
- amelius 9y ago> Because then you are compromising the utility of your url-as-search semantics Could you explain why?