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I believe, what Haskell is generating is list. What SETL is making, is set. Could this syntax be used over any monad? [edit] Of course, there are things like
by stralep 16y ago
I believe, what Haskell is generating is list. What SETL is making, is set.
Could this syntax be used over any monad?
[edit] Of course, there are things like */[1..n] for finding factorial, but that is fold in Haskell. It's neat for scripting, and for me, for circuit complexity explorations.
- kapuzineralex 16y agoSo all the fuzz is about the fact that SETL has builtin support for sets? Really, I don't mean to be a troll, but is that it?