3 ms·
A random X does not reduce the entropy of bcrypt(B), just fails to add any additional entropy beyond bcrypt(A)'s. Assuming C, where len(C) < 72, I don't know i
by crpatino 10y ago
A random X does not reduce the entropy of bcrypt(B), just fails to add any additional entropy beyond bcrypt(A)'s.
Assuming C, where len(C) < 72, I don't know if it is possible at all to chose some value of Y such that:
D:= C+Y
Entropy(bcrypt(D))< Entropy(bcrypt(C))
- Dylan16807 10y ago"Lose" meaning it is thrown away. Not "lose" meaning it subtracts.