4 ms·
Lifting a Million Pounds of Stainless Steel
- teh_klev 10y agoThere's some reasonable sized photo's of this monster here: http://www.nist.gov/pml/div684/grp07/million-pound-deadweight-restoration-continues-06262015.cfm http://www.nist.gov/pml/div684/grp07/million-pound-deadweigh...
- Tim61 10y agoThis would sound much less impressive if they just said 500 tons. Also, why the dead weight? 500 tons is easily doable with a (smallish) hydraulic press. The actual title of the article is "How Do You Lift A Million Pounds Of Stainless Steel?" I feel like they didn't answer that question either. It turns out that the weights are in fact lifted by hydraulics.
- goldenkey 10y agoI suppose it's a different shear force to apply all the weight at once rather than hydraulically.
- Retric 10y agoIt's a question of accuracy not maximum force. At some point you want to calibrate the things you use to calibrate the hydraulic presses. http://www.nist.gov/calibrations/index.cfm http://www.nist.gov/calibrations/index.cfm
- Animats 10y agoRight. Something the parent article completely fails to mention. This is NIST's force standard for large forces, the place you send load cells to be calibrated.[1] If they have to use the whole million pound stack, the fee is $16,489. [1] http://www.nist.gov/calibrations/force.cfm http://www.nist.gov/calibrations/force.cfm
- cmsmith 10y ago>Also, why the dead weight? 500 tons is easily doable with a (smallish) hydraulic press. Sure, but how do you know the hydraulic press is applying 500 tons? You need to have a universal standard for length (to determine the area of your piston) and for force (which doesn't exist), and consider the friction in your hydraulic system. We can generate a universal standard for the kilogram, then duplicate that log(500) times, and create a very well controlled mass that we can hang from stuff. The level of accuracy that is needed would surprise you.
- pstrateman 10y agoBecause 500 tons of dead weight is going to stay 500 tons. A hydraulic press would need to be calibrated.
- dsfyu404ed 10y agoThat's why it's "stainless" steel. Don't wanna gather up a bunch of oxygen molecules.
- cmsmith 10y agoI work at NIST and took a tour of this machine a few months ago. A few bonus facts: - The spatial distribution of the local gravity field is a significant part of the uncertainty of these measurements. The weights extend into the basement of the lab, and the gravity in the basement is less than that above the surface. They produce gravity maps by dropping things in a vacuum to get a handle on it. - The drift in the dead weight standard was mostly caused by the individual masses welding themselves together under the immense pressure of the weight stack. The interface has been designed to reduce this effect. - The same group is also working to count the number of atoms in the kilogram, so that the mass of the dead weight stack will not be 500,000 times the mass of a piece of platinum in Paris, but will be 500,000 times the mass of 6.XX E23 silicon atoms.
- deleted 10y ago[deleted]
- aftbit 10y agoMore about that piece of platinum in Paris, the International Prototype Kilogram (IPK): https://en.wikipedia.org/wiki/Kilogram#International_prototype_kilogram https://en.wikipedia.org/wiki/Kilogram#International_prototy... Also, something I had never heard of, Vienna Standard Mean Ocean Water: https://en.wikipedia.org/wiki/Vienna_Standard_Mean_Ocean_Water https://en.wikipedia.org/wiki/Vienna_Standard_Mean_Ocean_Wat...
- pif 10y ago> The spatial distribution of the local gravity field is a significant part of the uncertainty of these measurements. Interesting! Could you please add a few numbers, just to get the order of magnitude?
- yuubi 10y ago> why the dead weight? I assume it's because masses are more stable and easier to calibrate than the gauge on a hydraulic press.
- jaseemabid 10y agoWhy they don't use SI even for scientific measurements?
- venning 10y agoConsidering the machine was built in the US in 1965, it's not surprising that the machine used imperial units. Based on Wikipedia's table [1], it looks like metrication had not yet begun in a large number of countries by 1965. Also, if your goal is to build a device that calibrates other machines, and most of the machines in your country (and, likely, most of the machines belonging to the majority of your trading partners) use one system of measurement, then that's probably the system of measurement you build the machine to calibrate against. [1] https://en.wikipedia.org/wiki/Metrication#Conversion_process https://en.wikipedia.org/wiki/Metrication#Conversion_process
- jrapdx3 10y agoThat's an excellent way to express the situation back then. Given the ease of converting results with modern technologies, it's hardly a handicap to use the Imperial units, besides doing so preserves the "feel" of the era it came from. I think that's not a shabby or minor aspect of the machine being brought back to useful life.
- jrapdx3 10y agoMy guess is that when it was constructed 50 years ago, the "device" was engineered with the units that were familiar or already organized into formulas to plug data into. In the early to mid 60's, simple extremely limited dedicated calculators were a new thing and hard to get. Not at all like the tech in our world we take for granted, numerical analysis was much harder to accomplish. Of course today we have vast computation resources right under our fingertips. How hard is it to translate from one set of units to another? No doubt on issuing a report of their test results, the output will be expressed in whatever units anybody wants, no trouble at all...
- SAI_Peregrinus 10y ago
- gadders 10y agoNow they just need to try folding some paper 7 times, squash some playdoh animals and set up a YouTube channel and the thing will pay for itself: https://news.ycombinator.com/item?id=11694819 https://news.ycombinator.com/item?id=11694819
- dsfyu404ed 10y agoDid they put the tools back in the cabinet when they were done? That's a serious question.