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That's just Array.forEach in JS. Or in Scala: (1 to 5) foreach { _ => println("look, a line!") } That's really nothing to do with Sets.

• pbhjpbhj 10y ago
  Logically it can be expressed as operating on the set {1, 2, 3, 4, 5} - I think that's the point: one can perceive it differently, either as a set operation or as a loop/iteration.
  • ssmoot 10y ago
    module Numeric def times(&b) (1..self).each(&b) end end It's really no different than the Scala you'd write for the same thing: implicit class LongHelpers(l: Long) { def times(f: => Any) = (1L to l) foreach f } 10 times println("here's a line!") To interpret that as a Set operation would make the definition of a Set operation so broad as to be useless IMO.
  • nlpexprt 10y ago
    sets aren't ordered
    • pbhjpbhj 10y ago
      The set of ordered sets is a subset of the set of sets. Totally ordered sets, which I think are synonymous with chains(?), are still sets. But yes, I was talking loosely: my point was to differentiate between a mental model of iterating over a sequence (or ordered set) and applying a set-like transformation. My mental picture was of a field formed by a matrix operation on a limited space as being composed of the summation of a series of vector transformations; my maths language doesn't really allow me to properly describe it however. Loosely: you can break down a [subset of] 3D transformation[s] of a surface in to a series of 2D transformations performed iteratively, or you can apply a 3D transformation; they're different mental images of acquiring the same result.