4 ms·

It's pretty much as Velox and bbrazil said. You can use "low-coherence interferometry" to measure tiny signals that would be undetectable otherwise. Combine a

by Aeolos 11y ago

It's pretty much as Velox and bbrazil said. You can use "low-coherence interferometry" to measure tiny signals that would be undetectable otherwise. Combine a "reference" beam with a "signal" beam and you get a measurable interference pattern, even when the magnitude of the signal beam is miniscule. This is what a real-life interference pattern looks like (I just acquired this from an actual interferometer illuminating a painted metal surface): https://dl.dropboxusercontent.com/u/30682604/fringe_signal.png https://dl.dropboxusercontent.com/u/30682604/fringe_signal.p... This is now an established medical imaging method (Optical Coherence Tomography) to create 3d scans of biological tissue. It can also be used to measure distance or elevation changes on a surface of anything from a micrometer-level scale to a planetary surface. All you need is to use light with the right wavelengths and two measurements "arms" of roughly the same length.

sgrytoyr 11y ago
That does make sense, but I guess what I still don’t understand is how light can be reflected by a mirror (made of atoms) so precicely that it doesn’t hide sub-atomic differences. Won’t the light hit "different atoms" on the mirror, so to speak, thus changing the distance travelled by much more than fractions of the size of a single atom?
- jarin 11y ago
  From what I understand, it doesn't really matter because the laser light acts as a coherent wave, so it doesn't really bounce off of individual atoms, per se. As long as the mirrors are flat, all that matters is the relative distance between the mirrors.
- snowwrestler 11y ago
  > Won’t the light hit "different atoms" on the mirror, so to speak, thus changing the distance travelled by much more than fractions of the size of a single atom? Yes, it will, but that is already represented in the interference pattern. They're not measuring the absolute distance to the mirror. If they were, you are right about how the precision would be limited. Instead they're using the interference pattern to measure a change in the distance measurement over time. So even though the distance is somewhat of an average over many atoms, as long as it is the same mirror, it will be the same average at the same distance. Because the interference pattern represents photons interfering with each other, its precision is limited by the size of photons--which are much smaller than atoms.
  - Aeolos 11y ago
    Exactly. The imprecision of the mirror surface (and various other optical surfaces in the system) cause their own interference pattern that can be measured and subtracted from the recorded signal. Even so, measuring gravity waves requires ridiculous amounts of precision in the construction of the interferometer. I'm working at the 10^-6 scale, where optics can still be adjusted by hand. They are working at the 10^-21 scale - the sheer engineering challenge is awe-inspiring.
  - sgrytoyr 11y ago
    Thanks, excellent explanation.
Tepix 11y ago
Thanks. Btw: "how ... looks like" -> "what ... looks like"
- Aeolos 11y ago
  Cheers, fixed. I wrote this in a hurry while calibrating my device ;)

by Aeolos 11y ago

sgrytoyr 11y ago

That does make sense, but I guess what I still don’t understand is how light can be reflected by a mirror (made of atoms) so precicely that it doesn’t hide sub-atomic differences. Won’t the light hit "different atoms" on the mirror, so to speak, thus changing the distance travelled by much more than fractions of the size of a single atom?

jarin 11y ago
From what I understand, it doesn't really matter because the laser light acts as a coherent wave, so it doesn't really bounce off of individual atoms, per se. As long as the mirrors are flat, all that matters is the relative distance between the mirrors.
snowwrestler 11y ago
> Won’t the light hit "different atoms" on the mirror, so to speak, thus changing the distance travelled by much more than fractions of the size of a single atom? Yes, it will, but that is already represented in the interference pattern. They're not measuring the absolute distance to the mirror. If they were, you are right about how the precision would be limited. Instead they're using the interference pattern to measure a change in the distance measurement over time. So even though the distance is somewhat of an average over many atoms, as long as it is the same mirror, it will be the same average at the same distance. Because the interference pattern represents photons interfering with each other, its precision is limited by the size of photons--which are much smaller than atoms.
- Aeolos 11y ago
  Exactly. The imprecision of the mirror surface (and various other optical surfaces in the system) cause their own interference pattern that can be measured and subtracted from the recorded signal. Even so, measuring gravity waves requires ridiculous amounts of precision in the construction of the interferometer. I'm working at the 10^-6 scale, where optics can still be adjusted by hand. They are working at the 10^-21 scale - the sheer engineering challenge is awe-inspiring.
- sgrytoyr 11y ago
  Thanks, excellent explanation.

Tepix 11y ago

Thanks. Btw: "how ... looks like" -> "what ... looks like"

Aeolos 11y ago
Cheers, fixed. I wrote this in a hurry while calibrating my device ;)