yarg

9 ms·

91.
by yarg 2y ago
This actually reminds me of another claim that I think is wrong for the opposite reason; That that the Hilbert Curve covers the totality of the square; but the square contains all bound points of the form [real, real], and you can see from
92.
by yarg 2y ago
Seven sided never seemed that problematic to me? You can't do it exactly, but you can do it to arbitrary degrees of accuracy; at least about as far as you can go without bumping into the precision limits of a compass and straightedge.
93.
by yarg 2y ago
https://en.wikipedia.org/wiki/Write_once,_run_anywhere
94.
by yarg 2y ago
Yes the external format of a jar file is a zip - but there is also a specification for the internal structure and file formats, as well as information like the minimum java version required to execute (and all sorts of other crap, I can&#x2
95.
by yarg 2y ago
If you can't run jars, it's not a java implementation.
96.
by yarg 2y ago
The ability to launch a jar?
97.
by yarg 2y ago
It wasn't really a java implementation - they used the APIs, but broke compatibility.
98.
by yarg 2y ago
Funnily enough, I actually wrote code that does that very thing this morning.
99.
by yarg 2y ago
That reads like an XKCD alt-text. (That would've been RM; SKB is Stan Kelly-Bootle)
100.
by yarg 2y ago
Suicidal living under a creaking branch during a cyclone - it missed by a metre.
101.
by yarg 2y ago
> In your case, it appears you are operating in a Bayesian world but forcing your prior to be constantly uniform despite observing data. Got you now, thanks.
102.
by yarg 2y ago
I'll write some code to test it tomorrow, but why the hell would it be zero? There are other probabilities that can lead to zero successes - every probability except for one. And yes, they diminish rapidly as the number of trials goes
103.
by yarg 2y ago
With the simplified form of the binomial for n equal to k: ∫(0 -> x)(p^n)dp = ∫(x -> 1)(p^n)dp [p^(n+1)/(n+1)](0 -> x) = [p^(n+1)/(n+1)](x -> 1) x^(n+1) - 0^(n+1) = 1^(n+1) - x^(n+1) 2 * x^(n+1) = 1
104.
by yarg 2y ago
It was twenty years ago, but I think it was n + 1. I'll redo the maths and check.
105.
by yarg 2y ago
I just treated it as a binomial distribution with a fixed but unknown probability. Take the case of zero successes, that can happen for every probability except for one. The graph peaks at zero, but if you calculate 'x' such that
106.
by yarg 2y ago
I remember thinking about something similar to this at university - I was uncomfortable with the use of biases to assign non-zero probabilities to events that fail to occur after some number of trials. If I flip a coin n times and it comes
107.
by yarg 2y ago
Depends on the network; that sort of self evaluation certainly requires recurrency. But I don't think it's impossible - there's a certain psychedelic quality to hallucinations, they tend to over represent certain fundamenta
108.
by yarg 2y ago
It doesn't help that the term 'liberal' has had its meaning so co-opted that it now refers to people who reject freedom of speech and belief.
109.
by yarg 2y ago
Someone else shat the bed on the first project I worked on for the company. He blamed me, so for the next four years took every opportunity to had to fuck me over regardless of what I was trying to get done. I once had to get through six we
110.
by yarg 2y ago
What did it for me wasn't the fact that the project had no end in sight, It was the fact that every time I made an effort to move towards that point, the boss would pull in a dickhead architect (let's call him Huy) who would then
111.
by yarg 2y ago
Correct them? An incorrect answer can be useful, because it often illustrates common confusions and naive mistakes that people are prone to making; If it's corrected with an explanation as to why it doesn't work, a good wrong answ
112.
by yarg 2y ago
Makes me think of good/cheap/fast - pick two. You can't tell from the output price which selection was made.
113.
by yarg 2y ago
No, which you would've noticed if you were actually bothering to consider the other side of the argument and not simply dismissing it out of hand. Anyway, I can't be bothered with this anymore since I've completely lost the a
114.
Ask HN: My Sound Works?
1 points by yarg 2y ago|2 comments
115.
by yarg 2y ago
Refer to structural isomorphism above.
116.
by yarg 2y ago
No, I'm saying that the sliver of a chasm between the colour in isolate, and what I subconsciously imagine the midpoint to be, is so damned thin that were I to look at the colours side by side, I could not distinguish one from t'o
117.
by yarg 2y ago
No real need for the snark; if we dismiss the notion of human divinity and look at ourselves as broadly fixed macro-structure computational machines (like any other broadly deterministic machine) similar signals propagating over the same se
118.
by yarg 2y ago
I actually checked that at the end of the test (when it shows the gradient image with the response overlay). There were two distinct points, one for blue and one for green, where my mind would place the transition to the colour in between.
119.
by yarg 2y ago
Then call it something else. But the point stands that there's a point at and around which the colours are neither blue nor green.
120.
by yarg 2y ago
No it absolutely doesn't. It's a well know fact that people are unable to distinguish colours that are too close together. You could even have a smooth gradient from colour 'a' through colour 'b' to colour &#x2

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