3 ms·
In that case, the question should be, why am I attempting to convert one concrete type to another concrete type? If you're writing a program, you should use th
by cmma 11y ago
In that case, the question should be, why am I attempting to convert one concrete type to another concrete type?
If you're writing a program, you should use the same type, std::vector<char* >, everywhere.
If you're writing a library, the API should avoid including container details in function parameters, and const and non-const T should be allowed.
template<typename Container>
void foo1(Container const& c);
template<typename Iterator>
void foo2(Iterator first);
template<typename Iterator>
void foo3(Iterator first, Iterator last);
template<typename Iterator>
void foo4(Iterator first, std::size_t num);
template<typename T>
void foo5(std::vector<T> const& vec);
void foo6(char const* const* first, std::size_t num);
foo6 is a pretty good alternative here, imo:
std::vector<char*> vec(...);
foo6(&vec.front(), vec.size());
It would be cool if the compiler could figure templated type conversion out, but the crux of the issue is, as I understand it, that T<A> and T<A const> are not necessarily implemented the same way.
Also note that std::vector<std::string const> won't compile -- it wouldn't be copy-assignable -- so these issues mostly seem to arise specifically when dealing with C strings and/or C compatibility. And reinterpret_cast is amazingly helpful for porting from C.