3 ms·
FYI: FFTS [1] in many (most?) cases outperforms FFTW, without runtime calibration. It gets there by using a smarter algorithm algorithm. It doesn't have the bel
by fa 11y ago
FYI: FFTS [1] in many (most?) cases outperforms FFTW, without runtime calibration. It gets there by using a smarter algorithm algorithm. It doesn't have the bells and whistles of more complete libraries—e.g., restricted to power-of-two transforms for now—but hopefully this will change.
[1] http://anthonix.com/ffts/ http://anthonix.com/ffts/
- oh_sigh 11y agoIs that outperforms on all architectures/"runtimes"?