5 ms·
Isn't that the same as using vanilla laziness: > let xs = [1, 2, (xs !! 0) + (xs !! 1)] in xs [1, 2, 3] It's order independent as well: > let xs
by cousin_it 11y ago
Isn't that the same as using vanilla laziness:
> let xs = [1, 2, (xs !! 0) + (xs !! 1)] in xs
[1, 2, 3]
It's order independent as well:
> let xs = [(xs !! 1) - 1, (xs !! 2) - 1, 3] in xs
[1, 2, 3]
Why do you need loeb?
- rfw 11y agoI guess it finds fixed points over a functor without requiring you to have a reference to the functor (having about the same usefulness as `fix`).