4 ms·
In bob's setting, the computation system is not determined or fixed. It is open-ended... In intuitionistic mathematics, we of course accept that there is no Tu
by jonsterling 11y ago
In bob's setting, the computation system is not determined or fixed. It is open-ended...
In intuitionistic mathematics, we of course accept that there is no Turing computable halting oracle, but we do not rule out the possibility that there is some other effective oracle that can decide halting. (This is in contrast to recursive mathematics / Russian constructivism)