4 ms·

Does this bring us closer to having native docker support on OSX?

by zbyte64 11y ago

MikeKusold 11y ago
Unlikely. It appears that this is dependent on BSD's jails. https://github.com/kvasdopil/docker/blob/freebsd-compat/FREEBSD-PORTING.md https://github.com/kvasdopil/docker/blob/freebsd-compat/FREE...
isomorphic 11y ago
This is off-topic and not the same thing, but you should look into xhyve: https://github.com/mist64/xhyve https://github.com/mist64/xhyve ...and then: https://github.com/coreos/coreos-xhyve https://github.com/coreos/coreos-xhyve https://github.com/ailispaw/boot2docker-xhyve https://github.com/ailispaw/boot2docker-xhyve Previous discussion here: https://news.ycombinator.com/item?id=9690846 https://news.ycombinator.com/item?id=9690846
TickleSteve 11y ago
No, Its a popular misconception that OSX is based on BSD... its not. OSX is a MACH kernel with a BSD userland (read BSD compatibility layer) much the same as there exists a POSIX layer for Windows.
- danieldk 11y ago
  BSD runs in kernel-space as well to provide the typical UNIX functionality (BSD system calls, UNIX-style processes, etc). You can see this in the kernel sources for XNU, which contains a fairly sizable chunk of a BSD kernel: https://github.com/opensource-apple/xnu/tree/10.10/bsd https://github.com/opensource-apple/xnu/tree/10.10/bsd There were other projects that used comparable approaches, such as Lites: http://www.cs.utah.edu/flux/lites/html/ http://www.cs.utah.edu/flux/lites/html/ No, Its a popular misconception that OSX is based on BSD... its not. So no, this is not a misconception, it's actually true. Sure, there is BSD in userland as well, but the kernel is Mach and BSD.
- bstx 11y ago
  Well, it's not just the userland. The XNU kernel is a hybrid of Mach (tasks, threads, IPC, VM), BSD (processes, users, devices, networking, system calls, VFS) and IOKit (driver framework)

4 ms·

Does this bring us closer to having native docker support on OSX?

by zbyte64 11y ago

Does this bring us closer to having native docker support on OSX?

MikeKusold 11y ago
Unlikely. It appears that this is dependent on BSD's jails. https://github.com/kvasdopil/docker/blob/freebsd-compat/FREEBSD-PORTING.md https://github.com/kvasdopil/docker/blob/freebsd-compat/FREE...
isomorphic 11y ago
This is off-topic and not the same thing, but you should look into xhyve: https://github.com/mist64/xhyve https://github.com/mist64/xhyve ...and then: https://github.com/coreos/coreos-xhyve https://github.com/coreos/coreos-xhyve https://github.com/ailispaw/boot2docker-xhyve https://github.com/ailispaw/boot2docker-xhyve Previous discussion here: https://news.ycombinator.com/item?id=9690846 https://news.ycombinator.com/item?id=9690846
TickleSteve 11y ago
No, Its a popular misconception that OSX is based on BSD... its not. OSX is a MACH kernel with a BSD userland (read BSD compatibility layer) much the same as there exists a POSIX layer for Windows.
- danieldk 11y ago
  BSD runs in kernel-space as well to provide the typical UNIX functionality (BSD system calls, UNIX-style processes, etc). You can see this in the kernel sources for XNU, which contains a fairly sizable chunk of a BSD kernel: https://github.com/opensource-apple/xnu/tree/10.10/bsd https://github.com/opensource-apple/xnu/tree/10.10/bsd There were other projects that used comparable approaches, such as Lites: http://www.cs.utah.edu/flux/lites/html/ http://www.cs.utah.edu/flux/lites/html/ No, Its a popular misconception that OSX is based on BSD... its not. So no, this is not a misconception, it's actually true. Sure, there is BSD in userland as well, but the kernel is Mach and BSD.
- bstx 11y ago
  Well, it's not just the userland. The XNU kernel is a hybrid of Mach (tasks, threads, IPC, VM), BSD (processes, users, devices, networking, system calls, VFS) and IOKit (driver framework)