4 ms·
My process was: [3 5 7] [7 5 3] [8 4 2] [5 7 3] [1 2 3] [1 1 1] [0 1 2] At that point I could've done some more to be really certa
by ubernostrum 11y ago
My process was:
[3 5 7]
[7 5 3]
[8 4 2]
[5 7 3]
[1 2 3]
[1 1 1]
[0 1 2]
At that point I could've done some more to be really certain, but felt confident enough and guessed (correctly).
- jonkiddy 11y ago[16 32 64] [0 0 0] [1 2 3] [3 2 1] [-1 0 1] [3 5 7] [-2 -1 0] [111 54231 9999999999999999999999] At that point, I correctly answered the question.
- jws 11y agoSimilar to mine, but we both actually failed. Real numbers are accepted and we did not test that.
- WildUtah 11y agoIt accepts floating point numbers. To approximately double precision. But it accepts zero percent of real numbers.
- eru 11y agoI can nitpick better than that! To talk about a certain fraction of real numbers you have to have a distribution over them. In general we take the uniform distribution if no distribution is explicitly given. That doesn't work for real numbers (it doesn't even work for natural numbers). (See https://math.stackexchange.com/questions/14777/why-isnt-there-a-uniform-probability-distribution-over-the-positive-real-number https://math.stackexchange.com/questions/14777/why-isnt-ther...) If there's no implicit default distribution, we have to pick on. I can pick one where they cover an arbitrary high percentage of real numbers..
- elnion 11y agoDown the rabbit hole of pedantry: we don't need a distribution, just a measure, if we want to talk about how many reals it accepts. The Lebesgue measure is implied on the Reals if none is given, and the computable reals have measure zero. We can't reasonably talk about a percent coverage, since the Lebesgue measure of the reals is infinite, but as a non-technical description, 'zero percent' is morally equivalent to saying it only covers a measure-zero set.
- profinger 11y agoI did this plus also testing [1 1.5 2]
- perlgeek 11y agoSo you limited yourself to non-negative integers, and had no idea what negative numbers or fractions would do.
- eli 11y agoBased on the context of the question and the UI of the testing interface, fractions seem unlikely to be an intended part of the question. I likewise wouldn't bother testing unicode U+216x roman numerals.
- Ntrails 11y agoIt refused to accept both fractions and imaginary numbers. I did test negatives and zeros since that was really the only remaining set I could think of. Most importantly I used about 6 tests (3 right 3 wrong) to come up with the answer and then did another 17 looking for the trick. After all, it couldn't just be that simple right?
- bbcbasic 11y agoAlso he didn't know what numbers whose digits add up to 88 would do.
- __david__ 11y agoTheir input on the phone wouldn't allow minus or period characters so I assumed positive integers were the set.
- ubernostrum 11y agoThe presentation of the problem -- and I know that trusting the problem state is unwise sometimes in cognitive-bias tests, since many such tests are actually designed to be "we said we were asking X but actually meant Y" -- indicated a simple rule, rather than one which would behave differently on different classes of numbers. So after the tests listed above I felt confident enough to guess.