3 ms·
Interesting. Something I didn't realize: for n > 4, F(n) = F(n-2) * 3 - F(n-4) fibonacci sequence is defined as: F(n) = F(n-1) + F(n-2) substitute F(n-1) wit
by mariusz331 11y ago
Interesting. Something I didn't realize:
for n > 4,
F(n) = F(n-2) * 3 - F(n-4)
fibonacci sequence is defined as:
F(n) = F(n-1) + F(n-2)
substitute F(n-1) with F(n-2) + F(n-3):
F(n) = F(n-2) + F(n-3) + F(n-2)
substitute F(n-3) with F(n-4) + F(n-5):
F(n) = F(n-2) + F(n-5) + F(n-4) + F(n-2)
substitute F(n-4) with F(n-2) - F(n-3):
F(n) = F(n-2) + F(n-5) + F(n-2) - F(n-3) + F(n-2)
simplify:
F(n) = 3 * F(n-2) + F(n-5) - F(n-3)
because F(n-3) = F(n-4) + F(n-5), -F(n-4) = F(n-5)) - F(n-3):
F(n) = 3 * F(n-2) - F(n-4)
- deleted 11y ago[deleted]