3 msΒ·
Not to detract from your point, but you don't need the expansion for that. Directly substituting π in the definitional equation works just fine: L a = π
by tel 11y ago
Not to detract from your point, but you don't need the expansion for that. Directly substituting π in the definitional equation works just fine:
L a = π + a Γ (L a)
L π = π + π Γ (L π)
L π = π + (L π)
L π = π + π + π + π + π + π + ...
β = π + π + π + π + π + π + ...
The final expansion is worth writing, however, since it notes how there are unboundedly many naturals, each a different component in this infinite disjoint sum.