4 ms·
How would the regex below compare in this case? That is, modifying the "bad" regex to use the lazy-consumption trick on (almost) all of the `.` patterns. /.*
by Twisol 11y ago
How would the regex below compare in this case? That is, modifying the "bad" regex to use the lazy-consumption trick on (almost) all of the `.` patterns.
/.*? (.*?)\[(.*?)\]:.*/