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No. One-based indexing everywhere. So 8 / 4 is 2 with a "remainder" of 4. Think about it. If you have a series of bins with 4 items each, and you ask someone
by TheLoneWolfling 11y ago
No. One-based indexing everywhere.
So 8 / 4 is 2 with a "remainder" of 4.
Think about it. If you have a series of bins with 4 items each, and you ask someone to grab the 8th item, where do they go? To the 4th item of the second bin.
- Retra 11y agoThe fourth item of the second bin is the fourth item of the remaining items after you've looked at one bin.
- TheLoneWolfling 11y agoBut it is contained in the second bin.
- Retra 11y agoI get that. I'm not completely stupid. I'm saying that it is still a remainder. It can be a remainder and in the second bin at the same time.