3 ms·
Plus, most instructions are actually out-of-order on x86 (hence the out-of-order superscalar). So your "mov" will usually take (effectively) zero cycles -- unle
by pmalynin 11y ago
Plus, most instructions are actually out-of-order on x86 (hence the out-of-order superscalar). So your "mov" will usually take (effectively) zero cycles -- unless there is a dependency. But compilers are usually smart enough to pipeline the generated code, so the problem is really not a problem at all!