5 ms·

> ((D%C)+(B%C)) = (D+B) % C This is wrong. You need an extra %C on the left hand side for that identity to work: ((D%C)+(B%C))%C = (D+B) % C

• edmccard 11y ago
  In the J programming language, '%' is the division operator (not the modulus). So the identity is correct
  • mehrdada 11y ago
    Thanks, I missed it. My bad.