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You are almost certainly misstating the Haskell programmer's question, because C makes it very easy to test if two function pointers are equal (intensional equa
by ezyang 11y ago
You are almost certainly misstating the Haskell programmer's question, because C makes it very easy to test if two function pointers are equal (intensional equality) whereas Haskell makes it very hard.
- deleted 11y ago[deleted]
- derefr 11y agoI think they might have meant "whether two functions are structurally identical"—i.e. whether their post-link-load-phase object-code hashes the same, presuming they're both position-independent.