3 ms·
Not only incorrect How? immediately followed by an equation that disagrees with the statement I'm confused: are you saying that "The rate of change of the mo
by jamessb 11y ago
Not only incorrect
How?
immediately followed by an equation that disagrees with the statement
I'm confused: are you saying that "The rate of change of the momentum of a body equals the force acting on
the body" is inconsistent with the statement that F=ma for a body of constant mass? Because they are consistent:
F = dp/dt = d(mv)/dt
For constant mass, this is equal to m dv/dt = ma.
- deleted 11y ago[deleted]
- EliRivers 11y agoSon of a bitch. I misread it even as I copied it. I read "velocity" so read it as acceleration rather than dp/dt. That'll learn me to read more carefully.