2 ms·
Yes, the fact it's >O(n^k) for all k in [1,2) is why it's not strongly. It's still less than O(n^2).
by judemelancon 11y ago
Yes, the fact it's >O(n^k) for all k in [1,2) is why it's not strongly. It's still less than O(n^2).
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2 ms·