3 ms·
That is a risk, which is why you need to block all signals using the sigprocmask syscall before unmapping your stack.
by Amanieu 11y ago
That is a risk, which is why you need to block all signals using the sigprocmask syscall before unmapping your stack.
- geofft 11y agoOr you just don't have signal-handling functions. Signals only touch the stack if you handle them via functions. The default signal dispositions all either kill the process or do nothing, so they don't touch the stack.