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Edit: "Real" is, I suppose, arguable. By that I meant: Java's lambdas don't support mutation of captured variables. Then Haskell doesn't have closures either ;

Edit: "Real" is, I suppose, arguable. By that I meant: Java's lambdas don't support mutation of captured variables. Then Haskell doesn't have closures either ;). I think the definition of a closure is: a lambda abstraction / anonymous function that uses a free variable in its definition. So, Java's lambdas are real closures.

WalterGR 11y ago
Maybe I'm just biased because I was first introduced to closures by SICP, and so Scheme's take became my personal Platonic Ideal. :)
deleted 11y ago
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