Being pedantic: Erlang doesn't have a 32-bit intger type, it only has integers. The implementation uses the fixnum trick known from lisp, i.e. if the value is l

Being pedantic: Erlang doesn't have a 32-bit intger type, it only has integers. The implementation uses the fixnum trick known from lisp, i.e. if the value is larger than a fixnum it is implemented as a bignum.