69 ms·
What you say is correct, interpreting "primes" as meaning "the values 2, 3, 5, 7, 11, etc.". Every positive rational is essentially uniquely a product of finite
by Chinjut 11y ago
What you say is correct, interpreting "primes" as meaning "the values 2, 3, 5, 7, 11, etc.". Every positive rational is essentially uniquely a product of finitely many of these values raised to integer powers.
That having been said, what is it that makes these particular values "prime"? It's that they cannot be (nontrivially) decomposed into further factors. But in the rationals, they can be! 2 = 1.6 * 1.25, 3 = 1.6 * 1.875, etc. The inability to further factor 2, 3, 5, 7, 11, etc., which causes us to single them out as "prime" in the first place, is only on an account of factorization into whole numbers excluding such rational factorizations.
So it's in that context that my comment was to be understood: the fact that 6 specifically has the irreducible factorization 2 x 3 is not universally true, but only true in particular contexts, of which the most common would be the integers. In the mentioned context of the reals, or even just the rationals, we could instead note that 6 (or anything, really) could continue being divided indefinitely, thus having no particular "prime factorization" in the sense of a factorization which cannot be further refined.