3 ms·
> It will take that Sun an infinite amount of time to do that (drops below the Schwarzschild radius). Any conclusions you draw after that point are unscientific
by 4ad 11y ago
> It will take that Sun an infinite amount of time to do that (drops below the Schwarzschild radius). Any conclusions you draw after that point are unscientific.
Not true. You incorrectly assume that when the star collapses there is already an event horizon, somewhere. But it isn't. The event horizon will only form at some particular proper time, and at that time most (but not all) of the stellar mass will be trapped by the horizon and will form a singularity (interestingly all the trapped matter will reach the singularity at the same proper time).
This is all very clearly explained here: http://www.aei.mpg.de/~rezzolla/lnotes/mondragone/collapse.pdf http://www.aei.mpg.de/~rezzolla/lnotes/mondragone/collapse.p...
Related physics stack-exchange answer: http://physics.stackexchange.com/a/28837 http://physics.stackexchange.com/a/28837
I don't want to sound rude, but you really need to understand GR. The seminal work on the subject is "The Mathematical Theory of Black Holes" by Subrahmanyan Chandrasekhar, you need to know GR very well to be able to understand it, but the pdf I linked is comparatively much simpler on the GR and the mathematics required.
- ars 11y ago> You incorrectly assume that when the star collapses there is already an event horizon I made no such assumption. You don't need an event horizon to dilate time, just a massive gravitational field, and something resisting it. When the sun collapses either the outer layers experience a repulsive force of some kind from below (a bounce perhaps, which is already theorized for supernovas, or maybe neutron degeneracy), or the outer layers accelerate to nearly the speed of light, either way they dilate time, and from the POV of an outside observer take an infinite amount of time to collapse. Because of this dilation the rate of light output (as seen from outside) will drop and the sun will "turn off" - i.e. it will look [almost] identical to a black hole, except without the physics breaking singularity or event horizon. One visible effect will be extreme red-shift of the light, which will look (to us) like a very distant object hubble-red-shifted by distance/time.
- 4ad 11y ago> just a massive gravitational field There is no massive gravitational field inside a star.
- ars 11y agoIn the exact center, no. But there certainly is everywhere else in the star. After all, if there was no massive gravitational field, what's causing it to collapse? You can't have it both ways.
- yexponential 11y agoThank you both for this interesting discussion, helped me grasp a few things.