4 ms·
Based on your point 1, if time (on the outside) seems to speed up infinitely for the person falling into the black hole, and if the black hole will eventually e
by derekp7 11y ago
Based on your point 1, if time (on the outside) seems to speed up infinitely for the person falling into the black hole, and if the black hole will eventually evaporate due to hawking radiation, then wouldn't the black hole appear to completely evaporate prior to crossing the event horizon?
- amluto 11y agoIndeed. I never really understood how things ever actually make it through the horizon in the first place (as seen by far-away observers) in order to make the black hole grow. I /think/ what's going on is that, from the outside, you never really see a big black hole. Instead, you see what is, for all practical purposes, a big black hole, but really it's an exceedingly dense band of stuff, red-shifted to the point of invisibility, around the horizon. Of course, once you go close enough to inspect it for real, you get caught up in the time dilation enough that it looks more and more like a real black hole. If you go through the horizon, everything that ought to have preceeded you through the horizon already has, and it all makes sense. The math for this is quite hairy [1] and I suspect that we're mostly limited to numerical simulations. The closed-form steady-state black hole metrics are gnarly enough as is. [1] Terrible pun -- look up the "no-hair theorem"