2 ms·
No, the problem is the other way around. Keeping them as integers and just using '/' is what's causnig the problem. You can either force them to be floats (not
by IanCal 11y ago
No, the problem is the other way around. Keeping them as integers and just using '/' is what's causnig the problem. You can either force them to be floats (not the result, the parameters in the calculation), or you can explicitly look for divisions that have remainders.