4 ms·
Doing a bit of in-my-head math... At 1A, that'd be about 50g/day. I don't remember the voltage required for electroplating using CuSO4+acid, but I remember it
by tonyarkles 12y ago
Doing a bit of in-my-head math... At 1A, that'd be about 50g/day.
I don't remember the voltage required for electroplating using CuSO4+acid, but I remember it being low. I suppose it probably has to do with electrode spacing too. As a guesstimate, let's go for 5 volts (which I have no idea of the accuracy).
If we're stepping household 120V down to 5V, we've got a factor of 60 reduction. With a (big ass) buck converter, we can in theory get 15A*60 = 900A = 900C/s out of a standard breaker. That works out to 49kg/day? That seems ridiculously large. I'd love for someone to point out what I did wrong though. I've assumed 100% efficiency everywhere, but even cutting it down to 10% still results in ~5kg/day.
Edit: I'm sure it's an expensive power supply, but it's nice to see that I got in the right ballpark: http://www.americanplatingpower.com/reverse-pulse-power-axd-compact-s.php http://www.americanplatingpower.com/reverse-pulse-power-axd-...
- mschuster91 12y ago> With a (big ass) buck converter, we can in theory get 15A*60 = 900A = 900C/s out of a standard breaker No way you're gonna run 900A through this little pencil - the temperatures at contact point will act like a welding machine (uncontrollably melt/vaporize)...
- Turing_Machine 12y agoIndeed. You can probably run a lot more than normal if you keep the tip submerged and circulate the electrolyte, but you're not gonna run 900 amps through it. Some useful equations and numbers here: http://www.ami.ac.uk/courses/topics/0223_plate/index.html http://www.ami.ac.uk/courses/topics/0223_plate/index.html