2 ms·
I think if I split the cleaner node into two nodes, the standard solution has to change (not sure if there is one or not). It prevents the qubit needed to encod
by Strilanc 11y ago
I think if I split the cleaner node into two nodes, the standard solution has to change (not sure if there is one or not). It prevents the qubit needed to encode the information for the receiver from being in the same place as the qubit needed to decode the information from the sender, so no re-encoding.
┌───────┐
| |
| A ==> S
| || |
| || |
| vv v
| B ──> C
| |^╲ |
| | ╲╲ |
| | ╲╲ |
| v ╲vv
└>D────>R
Spot any solutions?