Which goes to show that what requires a 'new feature' in C# is just a freebie in Haskell, due to the powerful type system. See my other comment ITT for how to d

Which goes to show that what requires a 'new feature' in C# is just a freebie in Haskell, due to the powerful type system. See my other comment ITT for how to do this in a tighter way that is more like the C# syntax. (You just use the bind operator rather than wrapping it in a do)