4 ms·
It draws some doubt that the author lists accelerations in units of km/sec, not km/sec^2.
by acadien 12y ago
It draws some doubt that the author lists accelerations in units of km/sec, not km/sec^2.
- tesseract 12y agoIf you read "delta-v" for "acceleration" throughout the article, the whole thing makes more sense.
- maxerickson 12y agoThe author always says "an acceleration", which is the same thing as delta-v. I have no idea how particular it is to phrase it that way, but it isn't confused.
- acadien 12y agoThe author says multiple times: "an acceleration of [X] km/s is required", maybe they meant to imply that the magnitude of the change of the velocity?
- maxerickson 12y agoAccelerating at some rate km/ss for a period of s results in km/s. So the net result of "an acceleration" can be expressed as a velocity. (what it comes down to is that "an" is an indefinite article and always modifies a noun and km/ss is described by the verb acceleration. Yay English.)
- pwnna 12y agoIf i go from at rest (0m/s) to walking at 2m/s, I've completed an acceleration of 2m/s. Delta-v is common in orbital mechanics, which is often referred as "an acceleration".