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...and the strictness operator for ensuring that a function is applied to a value correctly. ($) isn't any kind of strictness operator -- maybe you're thinking
by shrughes 17y ago
...and the strictness operator for ensuring that a function is applied to a value correctly.
($) isn't any kind of strictness operator -- maybe you're thinking of ($!). ($) is a plain old function application operator.
- blasdel 17y agoIt's strictness for applicative precedence, as ($) is the least of the operators, like a greedy open-paren.