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Right. The basic idea is something like the transition (manifolds) from doing special relativity to general relativity. The special "linear" says that given two
by drostie 12y ago
Right. The basic idea is something like the transition (manifolds) from doing special relativity to general relativity. The special "linear" says that given two inputs x and y to a function f, f is linear if f(x + y) = f(x) ⊕ f(y) for two operations +, ⊕. The general "linear" says that f(x + δx) = f(x) ⊕ δf(x, δx) for some small perturbations δx in the vicinity of x.
If x is a bit-vector then this can be as simple as saying "flip one bit of the input and here's how to predict which output bits get flipped." When you're building a hash function in cryptography, you try to push the algorithm towards a non-answer here: about half the bits should get flipped, and you shouldn't be able to predict which they are. But of course there's a security vulnerability even if + and ⊕ are not XORs.
Resisting "adversarial perturbation" in this context means basically that neural nets need to behave a bit more like hash functions, otherwise they will confuse the heck out of us. The problem is that if you just took the core lesson of hash functions -- create some sort of "round function" `r` so that the result is r(r(r(...r(x, 1)..., n - 2), n - 1), n) -- seems like it'd be really hard to invent learning algorithms to tune.