3 ms·

void f(const Foo&_x){ Foo& x=const_cast<Foo&> (_x); … } What do you think is going on here?

• Tobani 12y ago
  > What do you think is going on here? I think you're adding code that doesn't address my point. This is pointer manipulation, not function call semantics. If you have raw pointers you can do a lot of magic. I think your code actually demonstrates how not-pointer like Java's references actually are.