5 ms·
Seems like a better name for it would be (...) :: (c -> d) -> (a -> b -> c) -> a -> b -> d since (...) = (.) . (.) .
by HanyouHottie 12y ago
Seems like a better name for it would be
(...) :: (c -> d) -> (a -> b -> c) -> a -> b -> d
since
(...) = (.) . (.)
.