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Since Haskell is lazy, how does packaging io into a chain of function calls guarantee ordering? Does it depend on some primitives being strict?
by fspeech 12y ago
Since Haskell is lazy, how does packaging io into a chain of function calls guarantee ordering? Does it depend on some primitives being strict?
- tome 12y agoThere's an internal representation which ensure than IO actions are evaluated in the correct order.