4 ms·
Actually even that is not feasible: Assume that you split a m byte string into k byte decompressor and l byte input data. If k+l < m, that is you actually comp
by yk 12y ago
Actually even that is not feasible:
Assume that you split a m byte string into k byte decompressor and l byte input data. If k+l < m, that is you actually compress, then there are only 2^(k+l) possible output strings. And since
sum_{i=0}^{m-1} 2^i = 2^m -1
there exists at least one string in the space of m character strings which can not be compressed by any algorithm.
- bagels 12y agoYes, knowing which string(s) to choose which have this property as the challenge giver is the hard part.