3 ms·
Am I incorrect in my normal usage of "x" when conveying relative performance? With 120.8498 vs 120.4320 being conveyed as "1.00 x slower". Is this the correct t
by brwnll 12y ago
Am I incorrect in my normal usage of "x" when conveying relative performance? With 120.8498 vs 120.4320 being conveyed as "1.00 x slower". Is this the correct terminology for results that are on par with each other? Really, these results are (relatively) unchanged. Shouldn't it be 0.003x slower, with the formula being (Old / New) - 1.
From the page:
Result Node.js v0.12.0
Called v2, util.yo("man") 100.000.000.000 times in 120.849870219 sec (1.00 x slower than v3)
Called v3, util.yo("man") 100.000.000.000 times in 120.432087601 sec
- sorenso 12y agoThanks for your comment. I agree that the semantic of this can be misinterpreted. It should have said "1.00 x the speed of v3". I'll change the text in my next run of this. I'm currently working on a new benchmark test of promises and callbacks. All in the name of performance :)