The only problem is that in C++, overloading operator[] has to be a non-static member function. x[y] is treated as x.operator[](y) if x is of class type. So x[y

The only problem is that in C++, overloading operator[] has to be a non-static member function. x[y] is treated as x.operator[](y) if x is of class type. So x[y] may not be the same as y[x] if they are class types. So maybe that has some useful property, but it isn't really the same.