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Well... you cannot call free on them, unless I'm mistaken. But other than that it's as normal. (This could be a problem if you want to call library code that f
by TheLoneWolfling 12y ago
Well... you cannot call free on them, unless I'm mistaken. But other than that it's as normal.
(This could be a problem if you want to call library code that frees a supplied pointer)
- Snaipe 12y agoAh, yes, good point. Great care should be taken for these cases to not happen.