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This looks great. From the examples, it seems that it is fully compatible with standard pointers with no need of casting. Is it true ? If so, it could work we
by minthd 12y ago
This looks great.
From the examples, it seems that it is fully compatible with standard pointers with no need of casting. Is it true ?
If so, it could work well in simplifying development with embedded development libraries, say like the mbed.
- Snaipe 12y agoYup, these are just pointers, usage is still the same, and no cast/special functions are needed to manipulate them.
- TheLoneWolfling 12y agoWell... you cannot call free on them, unless I'm mistaken. But other than that it's as normal. (This could be a problem if you want to call library code that frees a supplied pointer)
- Snaipe 12y agoAh, yes, good point. Great care should be taken for these cases to not happen.