3 ms·
Because most of PCs are windows machines. p(windows|vnc)=p(vnc|windows) * p(windows) / ( p(vnc|windows) * p(windows) + p(vnc|non-windows) * p(non-windows) )
by anonymfus 12y ago
Because most of PCs are windows machines.
p(windows|vnc)=p(vnc|windows) * p(windows) / ( p(vnc|windows) * p(windows) + p(vnc|non-windows) * p(non-windows) )